Solution

V1 = 440v, V2= 110V,

no load current = 5A, p.f = 0.9

Cos theta = 0.9,

theta = cos^-1 [0.9], theta = 25.84°

I) magnetizing current = no load current × sin theta

= 5×sin 25.84

= 5 × 0.44

magnetizing current, Im = 2.2A

II) core current = load current × cos theta

= 5×0.9

Ic = 4.5A

Iron loss = V1 × no load current × cos theta

= 440 × 5 × 0.9

= 1980W