Electrical maintenance and repairElectrical maintenance and repair EEC 226

How to find the value of a resistor with the following color code

Example 1

Find the value of a resistor with the following code.
1st band → brown
2nd band → black
3rd band → orange
4th band → silver

Solutions

BBROYGBVGW
Black = 0, brown = 1, red = 2, orange = 3, yellow = 4, green = 5, blue = 6, violet = 7, grey = 8, white = 9
Tolerance is
Gold ± 5%, silver ± 10%, no band/colour ± 20%
If the colour bands are brown, black and orange
Brown – 1
Black – 0
Orange – 3 ( i.e 3 zeros)
I.e 10 with 3 zeros or 10,000Ω


Question: HOW COME? 🤔

Ans: The third band indicate the number of zeros we’ll be having)

10,000Ω resistor with silver forth band, it’s value and tolerance will be 10,000 ohms plus or minus 10%


Question: HOW COME? 🤔

And: why is because silver represent 10%)


20% of 10,000 = 10/100 × 10000
= 1000Ω[ohms]Therefore, the resistor will have a value of 10,000 ± 1000
I.e 10,000+1000 or 10,000 – 1000 = 11,000Ω or 9,000Ω. ( 3 marks)

Example 2

Find the value of a resistor with the following color code.
1st band – brown
2nd band – red
3rd band – yellow
4th band – gold


Solutions
Brown = 1, red = 2, yellow = 4 (i.e 4 zeros), gold = 5%
The resistor is 120,000Ω
The resistor value for 120,000Ω of gold 4th band is;
120,000 × 5/100 = 6000Ω
Therefore, the resistor will have a value of 120,000 ± 6000
I.e 120,000 + 6000 = 126,000Ω
120,000 — 6000 = 114,000Ω
= 126,000Ω or 114,000Ω

Oluwamuyide Peter

My name is seyi, the main aim of creating this platform is to help users get information like school updates, electrical engineering topics and many more for free

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