Find the voltage V1 and V2 using kvl
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To Find V1 and V2, we’ll have to use ohm’s law and Kirchoff voltage law. Assume that current (I) flows through the loop
from ohm’s law, v = IR
so therefore, V1 = 4I,. V2 = -2I
Applying kvl around the loop given
-10 + V1 -8 – V2 = 0
-10 + (4i) -8 – (-2i) = 0
-10 + 4i -8 + 2i = 0
-18 + 6i = 0
6i = 18
i = 18/6; = 3A
so therefore, V1 = 4i; V2 = -2i
V1 = 4(3); 4×3. V2 = -2(3)
= 12V. =-6V