A coil consists of 2,000 turns of copper wire having a cross-sectional area of 0.8 mm2. The mean length per turn is 80 cm, and the resistivity of copper is 0.02 µ Ω-m. Find the resistance of the coil.
Length of the coil, L= Number of turns × mean length per turn
= 2,000 × 0.8 = 1,600 m
Cross-sectional area of wire, a = 0.8 mm2 = 0.8 × 10-6 m2
Resistivity of copper, ρ = 0.02 µΩ-m = 2 × 10-2 × 10-6 Ω-m = 2 × 10-8Ω-m
Current = V/R
Resistance of the coil, R = l/a = 2 × 10-8 × 1,600 / 0.8 × 10-6 = 40 Ω Ans.
Power = voltage × current
= V × I
Current = V/R
life VIDEO for this ASSIGNMENTS (the video consists of how we arrive at our answer).
Answer for resistance is 40 ohms
Power = 302.5W
AREA in mm squares = 10^-6. And not 10^-3
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Resistance and resistivity
Resistivity, power and resistance formulae, conductivity, temperature coefficient, circuit theorem and physics problem
29 thoughts on “A coil consists of 2000 turns of copper wire having a cross-sectional area of 0.8mm square. The mean length per turns is 80cm and the resistivity of copper is 0.02micro meter. Find the resistance of the coil and power absorbed by the coil when connected across 110v d.c supply.”
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