A coil consists of 2,000 turns of copper wire having a cross-sectional area of 0.8 mm2. The mean length per turn is 80 cm, and the resistivity of copper is 0.02 ยต โฆ-m. Find the resistance of the coil.
Solution:
Length of the coil, L= Number of turns ร mean length per turn
= 2,000 ร 0.8 = 1,600 m
Cross-sectional area of wire, a = 0.8 mm2 = 0.8 ร 10-6 m2
Resistivity of copper, ฯ = 0.02 ยตโฆ-m = 2 ร 10-2 ร 10-6 โฆ-m = 2 ร 10-8โฆ-m
Current = V/R
Resistance of the coil, R = l/a = 2 ร 10-8 ร 1,600 / 0.8 ร 10-6 = 40 โฆ Ans.
Power = voltage ร current
= V ร I
Current = V/R
= 110/40
= 2.75A
P= 2.75ร110
= 302.5W
Check Answer for resistance is 40 ohms
Power = 302.5W
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