CapacitorEngineering sciencePhysics

Three capacitor C1, C2, and C3 are connected in parallel to give an equivalent of 2μf. If the d.c supply, to the parallel combination of the capacitor is 20v, the capacitance of C1 is 0.5μf and the charged stored by C2 is 4Coloumb. Determine the capacitance of C2 and C3.Calculate the energy stored in the capacitor.

Three capacitor C1 C2 and C3 are connected in parallel to give an equivalent of 2μf. If the d.c supply to the parallel combination of the capacitor is 20v the capacitance of C1 is 0.5μf and the charged stored by C2 is 4Coloumb.
I. Determine the capacitance of C2 and C3.
II. Calculate the energy stored in the capacitor.


In series current is constant but in parallel voltage is constant.
Total capacitor (CT) = C1 + C2 + C3
Total capacitor (CT) = 2μf
Combined Voltage (V) = 20v
C1= 0.5μf
Q2= 4coloumb i.e 4c
Q2 is the charged stored by C2
C2= ?, C3 = ?
(CT) = C1 + C2 + C3
2=0.5+C2+C3 (we’ve two unknown which made it impossible to solve. So let’s find C2, since we’ve been given stored charge (Q)
Q2=Cv, Q2=C2•V
4=C2•20(since voltage is constant in parallel connection)
C2=4/20; = 0.2μf
(CT) = C1 + C2 + C3
2=0.5+0.2+C3; 2=0.7+C3
Therefore, C3 = 1.3μf

Find Energy stored

Energy stored,(E) = ½cv²; ½•0

½×2×400 = 400J


Oluwamuyide Peter

On the 4th of November I officially became a member of the exclusive 1st student with distinction after five years of no such record, in the history of The Polytechnic Ibadan, Faculty of Engineering to graduate with distinction as a DPP students since its establishment in 2011. My unrelenting power to solve problems, have made me to create a platform where student can get valid information anywhere, anyplace at anytime Evolving education world wide 🌎

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