A student measures a piece of rope and found it was 1.27 long. If the actual length of the rope was 1.25m, what was the percentage error in the measurement?

A student measures a piece of rope and found it was 1.27 long. If the actual length of the rope was 1.25m, what was the percentage error in the measurement?
Solution
(Initial length- actual length)/actual length × 100
1.27-1.25/1.25 × 100 = 0.02/1.25 × 100
0.016 × 100 = 1.6%

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